What is the range of the function y= √x+5

{f(x)∈R∣f(x)≥0}

Step-by-step explanation: The square root function never produces a negative result. Therefore, for the function f(x)=√x+5 , the domain is {x∈R∣x≥−5} and the range is {f(x)∈R∣f(x)≥0} .

Y>0

Step-by-step explanation:

To determine the range of this function, we must first evaluate the domain. The square root function is a nice, neat function as long as the radicand isn’t negative. In this function, the radicand becomes negative after x gets smaller than -5, so the domain of this function is [-5, infinity).

Now that we know the domain, we can calculate the range. Beginning with the left boundary, we can substitute -5 into the function to see what y equals at this x-value. At -5, y equals 0, so the minimum value for the range is 0; with the right boundary, substituting infinity yields infinity, so the range is any number greater than 0.

(x, y) → (x + 5, y – 3)

Step-by-step explanation:

Refer to a graph. It helps.

Up = +

Down = -

Right = +

Left = -