What is the rate of change of the perimeter of the square at the instant the area is 49 m2?

Let x = the length of a side of the square (m).
The area is
A = x²
The perimeter is
P =  4x

The rate of change of P with respect to x is
P'(x) = 4  (independent of x)

When A = 49 m², then x = 7 m.
The rate of P is 4.

4

19.8%

Step-by-step explanation:

We have the following formula for continuous compound interest:

A = P * e ^ (i * t)

Where:

A is the final value

P is the initial investment

i is the interest rate in decimal

t is time.

The time can be calculated as follows:

25 - 18 = 7

That is, the time corresponds to 7 years. In addition, A is 20,000 for A and P would be 5,000, we replace:

20000 = 5000 * e ^ (7 * i)

20000/5000 = e ^ (7 * i)

e ^ (7 * i) = 4

ln e ^ (7 * i) = ln 4

7 * i = ln 4

i = (ln 4) / 7

i = 0.198

Which means that the rounded percentage will be 19.8% per year