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27.06.2019 •
Mathematics
What is the recursive formula for the geometric sequence with this explicit formula an=9*(-1/3)^(n-1)
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Ответ:
Step-by-step explanation:
The explicit formula for the geometric sequence is given by:
where,
r is the common ratio to the following terms.
As per the statement:
Given the explicit formula for geometric sequence:
On comparing with [1] we have;
The recursive formula for geometric sequence is given by:
Substitute the given values we have;
Therefore, the recursive formula for the geometric sequence is,![a_n = a_{n-1} \cdot (-\frac{1}{3})](/tpl/images/0023/8111/9dbb9.png)
Ответ:
a_0 = -27
a_n = a_(n-1) * (-1/3)
Step-by-step explanation:
First evaluate given formula at n=0 and specify that as starting value
Then find how to get from n-1 to n by comparing two values. In this case the next value is formed by multiplying by -1/3.
Ответ:
Hello from MrBillDoesMath!
See Discussion below
Discussion:
A function f is even if f(-x) = f(x)
f(x) f(-x) Are they equal?
-x^8 + 2x^6-5x -(-x)^8 + 2(-x)^6 + 5x No
3 abs(x) - 4 3 abs(-x) -4 Yes
log5 x^2 log5 (-x)^2 Yes
(6x)^ (1/7) (-6x)^(1/7) No
e^(x^2-x) e^( (-x)^2+x) No
(x^8 +5x^2)^(-1) ( (-x)^8 + 5 (-x)^2) ^(-1) Yes
Answers with Yes, above are even functions.
Regards,
MrB
P.S. I'll be on vacation from Friday, Dec 22 to Jan 2, 2019. Have a Great New Year!