Mathematics: What is the remainder when (x3 − 3x2 − 13x + 78) is divided by (x + 4)?

6x-5Step-by-step explanation:We apply distributive property to get rid of the first parenthesis, by multiplying each term inside by the factor 1/6:now we get rid of the second parenthesis by multiplying the factor times each of the terms inside the parenthesis (notice here that this factor is negative , so it will flip the signs of the terms it multiplies):Next we combine like terms:...

What is the remainder when (x3 − 3x2 − 13x +

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bettylou12504

12.09.2020

Mathematics

6x-5

Step-by-step explanation:

We apply distributive property to get rid of the first parenthesis, by multiplying each term inside by the factor 1/6:

$\frac{1}{6} (30x+24)-\frac{1}{7} (63-7x)\\\frac{30}{6} x+\frac{24}{6} -\frac{1}{7} (63-7x)\\5x+4-\frac{1}{7} (63-7x)$

now we get rid of the second parenthesis by multiplying the factor " $-\frac{1}{7}$ " times each of the terms inside the parenthesis (notice here that this factor is negative , so it will flip the signs of the terms it multiplies):

$5x+4-\frac{1}{7} (63-7x)\\5x+4-\frac{63}{7} +\frac{7}{7} x\\5x+4-9+x$

Next we combine like terms:

$5x+4-9+x\\5x+x+4-9\\6x-5$

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What is the remainder when (x3 − 3x2 − 13x + 78) is divided by (x + 4)?

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