What is the solution of log∨4x − 6^16 = 4

x = 2

Step-by-step explanation:

I believe the equation you are trying to write is log of 16 with base of 4x-6 is equal to 4, and if that is the case then your answer is 4.

(3 + i)^2 * (1 -  2i)^2

( 1 + 2i)^2 * ( 1 - 2i)^2

Let's work on the denominator first.
((1 + 2i)(1 - 2i))^2
(1 - 4i^2)^2
(1 + 4)^2
25

now work on the numerator which does not look very nice.

((3 + i)(1 - 2i))^2
(3 -  6i + i - 2(i)^2 )^2
(3 - 6i + i + 2)^2
(5 - 5i)^2
25(1 - i)^2
25(1 - 2i + i^2)
25 (-2i)
-50i

Now put the two parts together
-50i / 25 = - 2i

There might be a shorter way to do this, but I don't know what it might be.