What is the solution to the equation? 4y – 12 = –4 a. y = 11 b. y = 2 c. y = –4 d. y = –13

Hi There!

What is the solution to the equation? 4y – 12 = –4 A. y = 11 B. y = 2 C. y = –4 D. y = –13

y=2

First simplify 
4y+-12=-4
Reorder the terms: 
-12+4y=-4
Move all terms containing "y" to the left, all other terms to the right.

Add 12 to each side of the equation:
 -12 + 12 + 4y = -4 + 12 

Combine like terms:
 -12 + 12 = 0
0 + 4y = -4 + 12
4y = -4 + 12
Combine like terms:
-4 + 12 = 8
4y = 8
Divide each side by '4'.
 y = 2

So your answer is B Y=2 
hope this helped 

11^2 + 9^2 = c^2
121 + 81 = c^2
202= c^2
Square root(202)= square root(c)
14.213= c
Hypotenuse = 14.213