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22.11.2019 •
Mathematics
What is the standard form of y=-(x-2)(x-3)(x-2)?
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Ответ:
y=-x^3+7x^2-16x+12
Step-by-step explanation:
y=-(x-2)(x-3)(x-2)
y=-(x^2-2x-3x+6)(x-2)
y=-(x^2-5x+6)(x-2)
y=-(x^3-5x^2+6x-2x^2+10x-12)
y=-(x^3-7x^2+16x-12)
y=-x^3+7x^2-16x+12
Ответ:
c
Step-by-step explanation: