What is the sum of 15 and x is greater than or equal to 12 minus y

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Ответ:

kamdenburr

04.11.2021

Mathematics

5) Given :

Side length of triangle (b) = 5.6 in

Hypotenuse of triangle (c) = 10.6 in

To find:

Length of side 'a'

Steps:

Using Pythagoras theorem

A² + B² = C²

We can find the missing length,

A² + (5.6)² = (10.6)²

A² + 31.36 = 112.36

A² + 31.36 - 31.36 = 112.36 - 31.36 (subtracting 31.36 from both sides)

A² = 81

$\sqrt{A^{2} } =\sqrt{81}$

A = 9 in

The length of side 'a' is 9 in

now using the same method for the rest of the questions, you will find

6) $\sqrt{15^{2} - 9^{2} }= \sqrt{225 - 81} = \sqrt{144} = 12 mm$

7) $\sqrt{26^{2}-10 ^{2} }=\sqrt{676 - 100} =\sqrt{576} = 24 cm$

$\sqrt{(12\frac{1}{3}) ^{2} -4^{2} }=\sqrt{(\frac{37}{3})^{2} -4^{2} }= \sqrt{\frac{1369}{9}-16 } =\sqrt{\frac{1369}{9} - \frac{144}{9} } = \sqrt{\frac{1369 - 144}{9} }= \sqrt{\frac{1225}{9} }= 35/3 yd$

Happy to help :)

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