What is the sum v of the twelve vectors that go from the center of a clock to
the hours 1: 00,2: 12: 00?
(b) if the 2: 00 vector is removed, why do the 11 remaining vectors add to 8: 00?
(c) what are the components of that 2: 00 vector v = (cos 6, sin 0)?

A. All cancel to produce the 0 vector.
b. Each one cancels its opposite except the 8:00 vector which is no longer cancelled by 2:00.
c. 2:00 is 1/3 of the way up from 3:00 x-axis to 12:00 y-axis so fie = pi/6
v= (cos pi/6, sin pi/6) = sqrt 3/2, 1/2
hope it helps

9.02 < x > 9.48.

I'm not quite sure, but the signs *might* have to be greater/less than or equal to, not just greater/less than. Anyways, it can't be an "or" situation because each pack needs to fit ALL criteria. This needs to be an "and" problem.