What is the surface area of a cylinder with a radius of 3 and a height of 7

The surface area of a cylinder includes the area of two circle bases as well as the tube connecting the bases.

Let's start with the circles. The area is pi*r^2.
pi*3^2 = 9pi

If we were to flatten a cylinder, this tube would actually be a rectangle with a length equal to the circumference of the circle. The circumference of a circle is 2pi*r.

So the rectangle has an area of 7*(2pi*3) = 42pi

There are two circular bases, so the surface area is:

2(9pi) + 42pi = 60pi
Or 60*3.14 = 188.4

The answer is below

Step-by-step explanation:

Function is a rule, or law that defines the relationship between one variable (the independent variable) and another variable (the dependent variable)

a) fog = f[g(x)] = f(1 - 2x) = 1 - 2x + 5 = 6 - 2x

b) foh = f[h(x)] = f(x - 2) = x - 2 + 5 = x + 3

c) goh = g[h(x)] = g(x - 2) = 1 - 2(x - 2) = 1 - 2x + 4 = 5 - 2x

d) gof = g[f(x)] = g(x + 5) = 1 - 2(x + 5) = 1 - 2x - 10 = 9 - 2x

e) hof = h[f(x)] = h(x + 5) = x + 5 - 2 = x + 3