What is the value of x in the figure? 40°
70°
OA 40°
OB. 70°
OC 80°
OD. 120°
OE
150°

it is B 70° because if you add 40° + 70° = 110°

so then you need to subtract that from 180°.

180° - 110° = 70°

D(2,1) E(3,5) , F(6,2)

DE=√17, EF=√18, FD=√17

distance=√(x2-x1)²+(y2-y1)²

DE : d= √(3-2)²+(5-1)² ⇒ d=√17

EF=√(6-3)²+(2-5)²=√18

FD=√(6-2)²+(2-1)²=√17

slope= m of( DE=4, EF=-1 , FD=1/4)

m=y2-y1/x2-x1

slope of DE=5-1/3-2 = 4

slope of EF=2-5/6-3=-3/3=-1

slope of FD=2-1/6-2=1/4

3- triangle is isosceles triangle , two sides are equal

DE=FD=√17