Mathematics: What is the vertex of -3x^2+6x+17 ?

What is the vertex of -3x^2+6x+17 ? - id326175016196, jalenrussell321

angelteddy033

18.01.2022

(1, 20)

Step-by-step explanation:

Given the quadratic function: -3x² + 6x + 17, this is the general form of the function ax² + bx + c. So, for the given function:

a = -3

b = 6

c = 17

The vertex can be found by solving for 'h' and 'k' using the following formulas:

h = $\frac{-b}{2a}=\frac{-6}{(22*-3)}=\frac{-6}{-6}=1\\$

k = $c-\frac{b^{2} }{4a}=17-\frac{6^{2} }{4(-3)}=17-\frac{36}{-12}=17+3=20$

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15.05.2020

Step-by-step explanation:

1) 3x(6x+5)

= 18x+15x

= 33x Answer

2) 4x(2x-3y)

= 8x-12xy Answer

Cannot be solved because it has unlike terms

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