antschilt519
26.09.2019 •
Mathematics
What is the vertex of the graph of the quadratic function y = x^2 6x 10? (3, -1) (-3, -1) (-3, 1) (3, 1)
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Ответ:
y=(x+6/2)^2-6/2^2+10
y=(x+3)^2-3^2+10
y=(x+3)^2-9+10
y=(x+3)^2+1
Ответ:
It is 4
Step-by-step explanation:
Because
1/2=2/x
x=2*2
x=4