What is the volume of the container needed to store 0.8 moles of argon gas at 5.3 atm and 227°c? . (given: r = 0.08205 l · atm/mol · k). 2.81 liters. 4.39 liters. 6.19 liters. 9.67 liters

6.19 L

Step-by-step explanation:

We are given that

Number of moles of argon gas=0.8 moles

Pressure =P=5.3 atm

Temperature =T=227 degree Celsius=

We have to find the volume of the container needed to store the argon gas.

We know that

Where R=0.082051 L atm/ mol k

Substitute the values in the given formula

Hence, the volume of container needed to store the gas=6.19 L

Hey friend,  Iam Bushra Azhar

Find the least square number which is exactly divisible by 8,12,15 and 20

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First,find the hcf of 8,12,15 and 20

8=2×2×2=2³

12=2×2×3=2²×3

15=3×5

20=2×2×5=2²×5

a number which is divisible by each of them should contain

2³x3x5

If it is a perfect square number,it should have even powers.

So,

2⁴×3²×5²=16×9×25

=3600

So,the answer is 3600

Hope it helps