Mathematics: What must be subtracted from a3b+6a2b2 -7ab+4 to get -7a2b2+2a3b+6ab-1?

What must be subtracted from a3b+6a2b2 -7ab+4

Ответ:

janahiac09

20.01.2022

Mathematics

$-a^{3} b+13 a^{2} b^{2}-13 a b+5$

Step-by-step explanation:

Let x be the expression, we have to find must be subtracted from the given expression, to get the answer.

Now we have to combine the like terms, before that we have to move x from LHS to the RHS , so that we will get the required expression.

$a^{2} b+6 a^{2} b^{2}-7 a b+4-x=-7 a^{2} b^{2}+2 a^{2} b+6 a b-1$

$a^{3} b+6 a^{2} b^{2}-7 a b+4+7 a^{2} b^{2}-2 a^{3} b-6 a b+1=x$

Now arranging the like terms as,

$\begin{array}{l}a^{3} b-2 a^{3} b+6 a^{2} b^{2}+7 a^{2} b^{2}-7 a b-6 a b+4+1=x \\-a^{3} b+13 a^{2} b^{2}-13 a b+5=x\end{array}$

So the expression is " $-a^{3} b+13 a^{2} b^{2}-13 a b+5$ "

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Ответ:

victoriahuntley12148

12.11.2020

Mathematics

Step-by-step explanation:

You have two congruent angles and the side between them. You can use the ASA Postulate to claim the triangles are congruent.

The SAS Postulate requires two congruent sides (there are 2 instances of S in the name SAS). You don't have that, so the SAS postulate cannot be used.

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What must be subtracted from a3b+6a2b2 -7ab+4 to get -7a2b2+2a3b+6ab-1?

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