grumpygreengori
18.11.2019 •
Mathematics
What, roughly, is the percent uncertainty in the volume of a spherical beach ball whose radius is r = 2.86 plus or minus .09 m?
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Ответ:
V = 4πr³ /3
where r is the radius of the given.
If the radius is 2.86, we can substitute the value to the equation above such that,
V = 4π(2.86)³ / 3 = 97.99π m³
When the radius is 0.09 m plus the given radius then,
V = 4π(2.86 - 0.09)³ / 3 = 89.03π m³
The difference between the volumes is equal to,
difference = 97.99π - 89.03π m³ = 8.96π m³
Dividing this to the original volume and multiplying by 100%,
percentage = (8.96π/97.99π) x 100%
percentage = 9.14%.
Hence, the expected percent uncertainty is equal to 9.14%.
Ответ:
p = 4
q = 6
s = 5
t = 4
a = 6
b = 7
m = 5
n = 6