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knikni06
05.01.2022 •
Mathematics
When 50% of a number is added to the number, the result is 135
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Ответ:
x+ (50% of x) = 135
x + (0.5x) = 135
1.5x = 135
x = 135/1.5
x = 90
Therefore, the number is 90
Ответ:
Let's call the unknown number x.
The problem tells us that when we add 50% of x to x itself, the result is 150. So the math looks like this:
x + (50% of x) = 150
x + (0.5x) = 150
1.5x = 150
x = 150/1.5
x = 100
We can check the math by taking 50% of 100 (which is 50) and adding it to 100. We get 150, so we know the math worked out!
Remember that percentages are just a different way of expressing fractions of 100. So "25%" = 25/100 = 0.25, and "50%" = 50/100 = 0.5, and so on.
Ответ:
Given:
Probability that the Yankees wins a game is
P(A) = 0.46
Probability that the Yankees loses a game is
P(A') = 1 - P(A') = 1 - 0.46 = 0.54
Probability that the Yankees scores 5 or more runs in a game is
P(B) = 0.59
Probability that the Yankees scores fewer than 5 runs in a game is
P(B') = 1 - P(B) = 1 - 0.59 = 0.41
Probability that the Yankees wins and scores 5 or more runs is
P(A⋂B) = 0.39
Applying the De Morgan's law, the probability that the Yankees scores fewer than 5 runs and they loses the game would satisfy:
1 - P(A'⋂B') = P(A) ⋃ P(B) = P(A) + P(B) - P(A⋂B)
or
1 - P(A'⋂B') = 0.46 + 0.59 - 0.39
or
1 - P(A'⋂B') = 0.66
=> P(A'⋂B') = 1 - 0.66 = 0.34
Applying the Bayes theorem, the probability that the Yankees would score fewer than 5 runs, given they lose the game:
P(B'|A') = P(A'⋂B')/P(A')
or
P(B'|A') = 0.34/0.54 = 0.630
Hope this helps!
:)