Where is the vertex of the quadratic y = (x -7)2 + 9

Try this option:
rule: common equation for a parabola is y=ax²+bx+c. If to re-write this equation in the form y=(x+m)²+n, then point (-m;n) is vertex of this parabola.
According to the described rule vertex is (7;9).
The graph of this function is in the attachment.

3. sqrt(58)

4. (-4.5, 2.5)

5. 15pi or 47.12388980385

Step-by-step explanation:

3. Distance is sqrt((x2-x1)^2 + (y2-y1)^2).

sqrt((6+1)^2 + (2+1)^2)

sqrt(7^2 + 3^2)

sqrt(49+9)

sqrt(58)

4. Midpoint is (1/2(x1+x2), 1/2(y1+y2))

(1/2(-8-1), 1/2(4+1)

(1/2(-9), 1/2(5))

(-4.5, 2.5)

5. C = piD

C = 15pi or 47.12388980385