Which could be the area of one face of the triangular prism? Select three options.
COS
10
[Not drawn to scale
24 square units
48 square units
72 square units
96 square units

24 square units

72 square units

96 square units

Step-by-step explanation:

In the figure attached, the complete question is shown.

One face is a rectangle with length = 12 and width = 8. Its area is: 8*12 = 96 square units

Another face is a rectangle with length = 12 and width = 10. Its area is: 10*12 = 120 square units

Another face is a rectangle with length = 12 and width = 6. Its area is: 6*12 = 72 square units

The other two faces are right triangles with base = 6 and height = 8. Their area is: (6*8)/2 = 24 square units

The surface area for this case is given by:
 A = 2 * pi * r ^ 2 + 2 * pi * r * h
 Where,
 r: radius of the coins
 h: height of the coin stack.
 Substituting values we have:
 A = 2 * 3.14 * (1/2) ^ 2 + 2 * 3.14 * (1/2) * (100 * (1/8))
 A = 40.82 in ^ 2
 Note: the correct thickness of the coins should be 1/8 in.
 
 Jose will need 40.82 in ^ 2 to cover the stack of coins