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The number of different ways to deal bridge hands to four players = 53644737765488792839237440000

Step-by-step explanation:

Total number of cards, N = 52

Each of the four players will receive (52/4) = 13 cards.

Each player 1, 2, 3 and 4 will receive

n₁ = 13, n₂ = 13, n₃ = 13, n₄ = 13

Distributing N different & unique objects into k distinguishable boxes such that nᵢ objects are place in box i (where i= 1,2, 3, 4k) can be done in

(n!)/(n₁!n₂!n₃!n₄!nₖ!)

So, for this problem, the number of different ways to deal bridge hands to four players = (52!)/(13!13!13!13!) = (52!)/(13!)4

= 53644737765488792839237440000

Hope this Helps!!!