Mathematics: Which equation represents a circle with the same radius as the circle shown but with a center at (-1, 1)? (x – 1)2 + (y + 1)2 = 16 (x – 1)2 + (y + 1)2 = 4 (x + 1)2 + (y –1)2 = 4 (x + 1)2 + (y – 1)2 = 16

Which equation represents a circle with the same

Ответ:

mv603177

10.01.2022

Mathematics

Last option: (x+1)^2+(y-1)^2=16

Step-by-step explanation:

The missing figure is attached.

The center-radius form of the circle equation is:

(x - h)^2 + (y-k)^2 = r^2

Where the center of the circle is at the poitn (h,k) and "r" is the radius.

You can identify from the figure attached that the radius of the circle shown is 4 units.

Since the other circle has the same radius and its center is at the point (-1, 1) ; you can identify that:

$h=-1\\k=1\\r=4$

Therefore, substituting values into (x - h)^2 + (y-k)^2 = r^2 , you get that the equation of that circle is:

$(x - (-1))^2 + (y-1)^2 = 4^2\\\\(x+1)^2+(y-1)^2=16$

Which equation represents a circle with the same radius as the circle shown but with a center at (-1

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Ответ:

nick607

10.01.2022

Mathematics

$\displaystyle (x + 1)^2 + (y - 1)^2 = 16$

Step-by-step explanation:

According to the Center-Radius Formula, $\displaystyle [X - H]^2 + [Y - K]^2 = R^2,$ [H, K] represents the centre of the circle, where the negative symbols give the OPPOSITE terms of what they really are, and the radius is ALWAYS squared. So, with the centre of $\displaystyle [-1, 1]$ plus your radius of 4, you have this: