Which equations represent the line that is perpendicular to the line 5x − 2y = −6 and passes through the point (5, −4)? check all that apply. y = –2/5x – 2 2x + 5y = −10 2x − 5y = −10 y + 4 = –2/5(x – 5) y – 4 =5/2 (x + 5)

The perpendicular equation is y = -2/5x - 2

You can find this by first realizing that perpendicular lines have opposite and reciprocal slopes. So since it starts at 5/2 we flip it and make it a negative and the new slope is -2/5. Now we can use that and the point to get the y intercept using slope intercept form.

y = mx + b

-4 = (-2/5)(5) + b

-4 = -2 + b

-2 = b

And now we can use our new slope and new intercept to model the equation.

y = -2/5x - 2

This equation is also equal to 2x + 5y = -10 and y + 4 = -2/5(x - 5)