Mathematics: Which function has only one x-intercept at (−6, 0)? f(x) = x(x − 6) f(x) = (x − 6)(x − 6) f(x) = (x + 6)(x − 6) f(x) = (x + 6)(x + 6)

5*9 = 45so7*9 = 6345/x=5/745/63=5/7 or x = 63...

Which function has only one x-intercept at (−6,

StupidBoy

09.01.2022

f(x)=(x+6)(x+6)

Step-by-step explanation:

Let's find the roots of every function:

x(x-6)=0

Expand the left side:

x^2-6x=0

Using quadratic formula:

$ax^2+bx+c=0\\x=\frac{-b\pm \sqrt{b^2-4ac} }{2a}$

Therefore:

$x=\frac{-(-6)\pm \sqrt{36-(4*1*0)} }{2*1} =\frac{6\pm \sqrt{36} }{2}=\frac{6\pm 6 }{2}$

Hence, the first function has two roots:

$x=6\\or\\x=0$

Analizing the second function:

(x-6)(x-6)=0

It's easy to see that it has a repeated root at x=6

Now, the third function:

(x+6)(x-6)=0

Also, it's simple to conclude that it has two roots at x=6 and x=-6

Finally the fourth function:

(x+6)(x+6)=0

has a repeated root at x=-6, which satisfies the problem condition

Aditionally I attached the graph of every function, so you will be able to check the result easily.

0,0(0 оценок)