Which function passes through the points (2, 15) and (3, 26)?
a) y=11x+7
b)y=11x-7
c)y=7x+11
d)y=-11x-7
e)y=7x-11

 The correct option is (B)

Step-by-step explanation:  We are given to select the function that passes through the points (2, 15) and (3, 26).

Since the function passes through two points, so it must be a linear function in two variables.

That is, the graph of the function will be a straight line.

Now,

the slope of the line passing through the points (2, 15) and (3, 26) is given by

Since the line passes through the point (2, 15), so the equation of the line will be

Thus, the required function is

Option (B) is correct.

-2+sqrt(3)

Step-by-step explanation:

When cos(angle)=sqrt(3)/2

then sin(of that angle)= + or - 1/2 depending on the quadrant

Anyways 330 degrees is in the 4 quadrant.  Cosine is positive there while sine is negative.

so sin(330)=-1/2

Formula for tan(x/2)=(1-cos(x))/sin(x)

Therefore  tan(165)=tan(330/2)=(1-cos(330))/sin(330)=(1-sqrt(3)/2)/(-1/2)

Multiply top and bottom by 2 to get

tan(165)=(2-sqrt(3))/-1

tan(165)=-2+sqrt(3)