Glamis856
14.07.2019 •
Mathematics
Which is the equation of a circle with a radius of 2 and it's center at (-4,3)?
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Ответ:
(x - xc)² + (y - yc)² = r²
Where xc and yc are center coordinates
(x - (-4))² + (y - 3)² = 2²
x² + 2.x.4 + 4² + y² - 2.y.3 + 3² = 4
x² + 8x + 16 + y² - 6y + 9 = 4
x² + y² + 8x - 6y + 25 - 4 = 0
x² + y² + 8x - 6y + 21 = 0
Ответ: