Which of the following equations is of a parabola with a vertex at (3, 0)? y = (x - 3) 2
y = (x + 3) 2
y = x 2 - 3
y = x 2 + 3

The answer is y = (x - 3)^2.

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y = 6x + 3

Step-by-step explanation:

Since you can't have a negative y in a y = mx + b equation you have to make it postive. You also have to do everything you do on one side to the other. To do this you have to multiply everything by -1. This will make everything positive b/c it cancels out the other negative. (Two negatives equals a positive) You should be left with y = 6x + 3. The -1 cancelled the -y, -6x, and -3 so you add 3 instead of subtract it.

y = 6x + 3