)) which of the following is a solution to the inequality below?
n
11
n = 11
n
= 4
n
= 2
n = 1
00

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Ответ:

theresamarieuehling2

12.03.2020

Mathematics

d^3-12d^2b+48db^2-64b^3

Step-by-step explanation:

By the binomial theorem,

$(p+q)^n=\sum_{r=0}^n ^nC_r p^{n-r} q^r$

Where,

$^nC_r=\frac{n!}{(n-r)! r!}$

Thus,

$(d-4b)^3=(d+(-4b))^3=\sum_{r=0}^3 ^3C_r (d)^{3-r} (-4b)^r$

$=^3C_0 (d)^{3-0} (-4b)^0+^3C_1 (d)^{3-1} (-4b)^1+^3C_2 (d)^{3-2} (-4b)^2+^3C_3 (d)^{3-3} (-4b)^3$

=d^3 +3(d^2)(-4b)+3(d)(16b^2)-64b^3

=d^3-12d^2b+48db^2-64b^3

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)) which of the following is a solution to the inequality below? n 11 n = 11 n = 4 n = 2 n = 1 00