Which of these cannot represent the lengths of the sides of a right triangle?
a. 3ft, 4ft, 5ft
b. 6in, 8in, 10in
c. 16cm, 63cm, 65cm
d. 8m, 9m, 10m

Choice D. 8m, 9m, 10m

Explanation:

If a = 8 and b = 9 are the two legs of a triangle and c = 10 is the hypotenuse, then

a^2 + b^2 = c^2

8^2 + 9^2 = 10^2

64 + 81 = 100

145 = 100

We get a false equation as 145 and 100 are two different values. So the original equation is false when (a,b,c) = (8,9,10)

By the converse of the pythagorean theorem, we have proven that this particular triangle is not a right triangle

Contrast this with something like choice A where we have a = 3, b = 4, c = 5 leading to

a^2 + b^2 = c^2

3^2 + 4^2 = 5^2

9 + 16 = 25

25 = 25

we get a true equation so a triangle with sides 3,4,5 is a right triangle. Choices B and C follow a similar path.

Alright mate, lets do some math!
We are trying to find the height of each hay bale right? So we need to divide the volume by the length and the width... so:
H = (10 2/3ft^3) diveded by (1 1/3ft x 4ft)
H = 2 ft
There are 8 bales of hay mate, so we have to multipy that by the H... so 2x8= 16ft.
Hope this helped!