Mathematics: Which of these points will lie on quadrant II of a coordinate plane? A. A(-4, -3) B. D (-4, 3) C. R (4, 3) D. G (4, -3)

the total charge isStep-by-step explanation:Since x is measured from the center, that means that x=0 is the center so the edges of the rod correspond to x=-6 and x=6. that meas that the total charge can be calculated asseparating the integral from -6 to 0 and from 0 to 6, taking into account that |x|=-x for x 0 and |x|=x for x =0, we getusing the substitution x=-u in the first integral we getwhich is the same as the first integral. Thus, the total charge is given byintegrating we get...

Which of these points will lie on quadrant II - id10730739, dontcareanyonemo

Ответ:

miarobless12389

18.03.2022

Mathematics

B. D (-4, 3)

Step-by-step explanation:

In quadrant II x value is -ve and y value is positive.

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Ответ:

kbuhvu

03.02.2021

Mathematics

the total charge is

$Q=24(1-\exp(-1))nC\approx15.171nC$

Step-by-step explanation:

Since x is measured from the center, that means that x=0 is the center so the edges of the rod correspond to x=-6 and x=6. that meas that the total charge can be calculated as

$Q=\int^{6}_{-6}2\exp\left(\frac{-|x|}{6}\right)dx$

separating the integral from -6 to 0 and from 0 to 6, taking into account that |x|=-x for x<0 and |x|=x for x >=0, we get $Q=\int^{0}_{-6}2\exp\left(\frac{x}{6}\right)dx+\int^{6}_{0}2\exp\left(\frac{-x}{6}\right)dx$

using the substitution x=-u in the first integral we get $\int^{0}_{-6}2\exp\left(\frac{x}{6}\right)dx=-\int^{0}_{6}2\exp\left(\frac{-u}{6}\right)du=\int^{6}_{0}2\exp\left(\frac{-u}{6}\right)du$

which is the same as the first integral. Thus, the total charge is given by

$Q=2\int^{6}_{0}2\exp\left(\frac{-x}{6}\right)dx$

integrating we get

$Q=4(-6\exp\left(\frac{-x}{6}\right))\big|^{6}_{0}=-24(\exp(-6/6)-\exp(0))=24(1-\exp(-1))$

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Which of these points will lie on quadrant II of a coordinate plane? A. A(-4, -3) B. D (-4, 3) C. R (4, 3) D. G (4, -3)

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