Which of these sortition methods can be used to select a person for a certain task from among 24 candidates? throw 2 dice. assign a combination (for example 5-6) to each candidate. flip a coin 5 times. assign a sequence (for example h-t-h-h-t) to each candidate. roll a dice 1 time and flip a coin 2 times. assign a sequence (for example 4-h-t) to each candidate. flip a coin and roll 2 dice. assign a sequence (for example h-3-4) to each candidate.

Rolling 1 die and flipping a coin 2 times would be the correct method.

There are 24 candidates so we need an experiment that has 24 different outcomes. To find the total number of outcomes, you multiply the number of outcomes for each individual part of the trial.

A dice has 6 outcomes and each coin has 2.

6 x 2 x 2 = 24

Rolling 1 die and flipping a coin 2 times would be the correct method.

There are 24 candidates so we need an experiment that has 24 different outcomes. To find the total number of outcomes, you multiply the number of outcomes for each individual part of the trial.

A dice has 6 outcomes and each coin has 2.

6 x 2 x 2 = 24

Step-by-step explanation:

Step-by-step explanation:

Given that a student conducted a study and reported that the 95% confidence interval for the mean ranged from 46 to 54

Hence width of interval = 8

Margin of error = ±1/2 (width)=±4

Margin of error = Z critical for 95%( std  error)

Equate the two terms for margin of error we get

(\frac{16}{\sqrt{n}=

n=61.4656

So sample size is approximately 61.