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dntestkly7509
30.08.2021 •
Mathematics
Which one of these are literal equations???
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Ответ:
m=(y2-y1/x2-x1)
m=(2-1/3--3)
m= (1/6)
Then, I put the numbers in slope intercept form first,
y-1=(1/6)(x-(-3))
Now change it to standard form:
( y-1=(1/6)(x-(-3)) ) times 6
6y-6=1(x+3) minus x on both sides and plus 6 on both sides and get the
6y-x=9
And you can plug the numbers in to check