Which set of ordered pairs goes with y = 2cos x ?

Set of ordered pairs = { ( 0 , 2 ),  ( π / 2 , 0) ,  ( π , -2) , ( 2 π , 2)}

Step-by-step Explanation:

Given  y = 2 cos x

i) Let  x =0 ⇒ y = 2 cos (0) = 2

The ordered pair ( 0 , 2 )

ii) Let x = π / 2  ⇒ y = 2 cos (π/2) = 2(0) =0

The ordered pair ( π / 2 , 0)

iii) let x = π ⇒ y = 2 cos(π) = 2 (-1) = -2

The ordered pair ( π , -2)

iv)

let x = 2π ⇒ y = 2 cos(2π) = 2 (1) = 2

The ordered pair ( 2 π , 2)

Set of ordered pairs = { ( 0 , 2 ),  ( π / 2 , 0) ,  ( π , -2) , ( 2 π , 2)}

150ft²

Step-by-step explanation:

Front facing rectangle: lw=6*5=30

Back facing rectangle: lw=6*5=30

Top facing rectangle: lw=2*6=12

Bottom facing triangle: lw=10*6=60

Trapezoid: (h(a+b))/2=(3(2+10))/2=3(12)/2=36/2=18

Total surface area = 30+30+12+60+18=150ft²