Which trig ratio? Can you solve this??

Step-by-step explanation:

There are six trigonometric ratios, sine, cosine, tangent, cosecant, secant and cotangent. These six trigonometric ratios are abbreviated as sin, cos, tan, csc, sec, cot. These are referred to as ratios since they can be expressed in terms of the sides of a right-angled triangle for a specific angle θ.

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Step-by-step explanation:

Using the Cosine rule to find AC

AC² = BC² + AB² - (2 × BC × AB × cosB )

      = 18² + 12² - ( 2 × 18 × 12 × cos75° )

      = 324 + 144 - 432cos75°

      = 468 - 111.8

      = 356.2 ( take the square root of both sides )

AC = ≈ 18.9

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Using the Sine rule to find ∠ A

= ( cross- multiply )

18.9 sinA = 18 sin75° ( divide both sides by 18.9 )

sinA = , then

∠ A = ( ) ≈ 66.9°