Which values are solutions to the inequality below?check all that apply .

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Ответ:

jettskii214

11.12.2022

Mathematics

(x+3)^2+(y+5)^2=36

Step-by-step explanation:

The information we have about the circle is:

center: (-3, -5)

and the radius: r=6u

the general form of the equation for a circle whose center is at (h,k) is as follows:

(x-h)^2+(y-k)^2=r^2

in this case since the center is at (-3, -5) , h and k are:

h=-3

k=-5

and we substitute this values, and the value of the radius into the general equation:

(x-(-3))^2+(y-(-5))^2=6^2

simplifying this expression we get:

(x+3)^2+(y+5)^2=36

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