Mathematics: Wich size bag of cat food show in the table has the lowest price

Wich size bag of cat food show in the table has

Ответ:

jorgelive5870

09.01.2022

Mathematics

The 40 oz cat food costing $8.00 is the lowest cost.

Step-by-step explanation:

Here, to compare the price of the cat food we need to find the UNIT RATE of the cat food of each size bag.

24 oz bag cost $5.49.

⇒ Cost of 1 oz cat food = $\frac{5.49}{24 } =0.22875$

or, the cost of 1 oz of cat food here is $0.22875.

40 oz bag cost $8.00.

⇒ Cost of 1 oz cat food = $\frac{8}{40 } =0.20$

or, the cost of 1 oz of cat food here is $0.20.

64 oz bag cost $15.99.

⇒ Cost of 1 oz cat food = $\frac{15.99}{64 } =0.2498$

or, the cost of 1 oz of cat food here is $0.2498.

Now, comparing the cost of 1 oz of cat food we seen that the lowest price of cat food per oz is $0.20 in the 40 oz pack.

Hence, the 40 oz cat food costing $8.00 costs the least.

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Ответ:

Liantic

09.01.2022

Mathematics

Size 40 oz bag of cat food has the lowest price.

Step-by-step explanation:

Given are the three category of different size of bag having different cost.

Lets try to find out the cost of one unit of bag for each category.

(i) Size = 24

Cost= 5.49

To find one unit of bag price, divide cost by size of bag

One unit of bag cost = $\frac{5.49}{24} = \$0.23$

∴ One unit of bag cost is $\$ 0.23$

(ii) Size= 40

Cost= 8

One unit of bag cost = $\frac{8}{40} = \$0.20$

∴ One unit of bag cost is $\$ 0.20$

(iii) Size= 64

Cost= 15.99

One unit of bag cost= $\frac{15.99}{64} = \$0.25$

∴ One unit of bag cost is $\$ 0.25$

∵ $\$ 20$ is the lowest price among all three bags of cat food.

∴ Size of 40 oz bag has the lowest price.

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Ответ:

skwmks8924

22.04.2023

Mathematics

4.01% probability that the cable company will keep the shopping channel.

Step-by-step explanation:

For each subscriber, there are only two possible outcomes. Either they watch the shopping channel at least once a week, or they do not. This means that we can solve this problem using the binomial probability distribution.

However, we are working with samples that are considerably big. So i am going to aproximate this binomial distribution to the normal.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

In this problem, we have that:

n = 100, p = 0.20

E(X) = 100*0.20 = 20

$\sqrt{V(X)} = \sqrt{100*0.20*0.80} = 4$

The cable company has decided to keep the shopping channel if the sample proportion is greater than 0.27. What is the approximate probability that the cable company will keep the shopping channel, even though the true proportion who watch it is only 0.20?

This probability is 1 subtracted by the pvalue of Z when X = 0.27*100 = 27 . So