(will give brainliest) a hiker, whose eye is 1.6 meters above ground, stands 50 meters from the base of connecting her eye and the top of the cliff and a horizontal line is 58°. draw a diagram representing the situation and find the height of the cliff

Step-by-step explanation:

Find the diagram attached. Using SOH, CAH, TOA to find the height of the cliff AC,

AC is the opposite side and BC is the adjacent

Given BC = 50m and ∠ABC = 58°

tan∠ABC = AC/BC

tan58° = AC/50

cross multiply

AC = 50tan58°

AC = 80.02m

Hence the height of the cliff is 80.02m

18/24 and 2/24

Least common denominator is 24