Will give brainliest! For a standard normal curve, find the z-score that corresponds to the 90th percentile. Please show how you got the answer thanks!

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Ответ:

chrisgonzalez33

23.09.2022

Mathematics

option A

Step-by-step explanation:

$\frac{x^a}{x^b} = x^{a-b}$ , z^0 = 1

So,

$\frac{18x^5 y}{6xy^8z^0} = \frac{18}{6} \times x^{5 -1} \times y^{1-8} = 3 x^4 \times y^{-7} = \frac{3x^4}{y^7}$

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