WILL GIVE BRAINLIEST! Prove that a quadrilateral ABCD with vertices A(–1, –2), B( 2, –5), C(1, –2), and D( –2, 1) is a parallelogram. Find the point of intersection of the diagonals of parallelogram ABCD. Provide your complete solutions and proofs in your paper homework and enter the numeric answers online.

(0,-2)

Step-by-step explanation:lol rsm hw

ok so just take average of two points (-1, -2) (1, -2)

-1+1=0/2=0

-2+(-2)=-4/2=-2

You can do this with B and D too

Have fun in rsm

A

Step-by-step explanation:

Use rise over run. The graph rises by 9 units between the 2 points and runs 3 units on the x axis.

Rise/ run = , which can be simplified to 3.

The slope is 3.