WILL GIVE BRAINLIEST!
The Kappa Beta fraternity has 200 sweatshirts and 100 pairs of sweatpants available to sell. During rush week, they decided to offer two package deals to students. Package A has one sweatshirt and one pair of sweatpants for $30. Package B has three sweatshirts and one pair of sweatpants for $50. The fraternity wants to sell at least 20 of Package A and at least 10 of Package B. How many of each package type must they sell in order to maximize their revenue?

50 A and 50 B

Step-by-step explanation:

A》20

B》10

A + B》100 (for pants)

A + 3B》200 (for shirts)

A = 20

A + 3B = 200

3B = 180

B = 60

(20,60)

B = 10

A + B = 100

A = 90

(90,10)

A + B = 100

A = 100 - B

A + 3B = 200

100 - B + 3B = 200

2B = 100

B = 50

A = 100 - 50 = 50

(50,50)

Revenue:

30A + 50B

(20,10): 30(20) + 50(20)

= 1,100

(20, 60): 30(20) + 50(60)

= 3,600

(90,10): 30(90) + 50(10)

= 3,200

(50,50): 30(50) + 50(50)

= 4,000

3x-13+2x+4=116( the sum of two interior angle is epual to the sum of exterior angle )

5x =116-9

5x=107

x=21.4 degree

then

angle a= 3*21.4-13

a=51.2degree

angle b=2*21.4+2

b =44.8degree

Step-by-step explanation:

plz make me brainliest