Will give (-5x)=(6x+12)

2 is the base in both logs
-5x is the argument in the first log
6x+12 is the argument in second log

find the domain and the solution to x

Ps: just starting on algebra, so might not be right.

Find the domain by finding where the equation is defined.

Interval Notation:

(−2,0)∪(5,∞)

Set-Builder Notation:

{x|−2<x<0,x>5}

Solve for x

For two functions to be equal, the arguments of each must be equal.

x=12,−1

I hope this isn't wrong and if it is, sorry...