ErrorNameTaken505
30.06.2019 •
Mathematics
Will make ! factor using the identity: a3 + b3 = (a + b)(a2 – ab + b2) 8z3 + 27 a.(2z + 3)(z2 – 6z + 9) b.(2z + 3)3 c.(8z3 + 27)(8z2 – 16z3 + 729) d.(2z + 3)(4z2 – 6z + 9)
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Ответ:
(2 z + 3) (4 z^2 - 6 z + 9)
Step-by-step explanation:
8z3 + 27
a = 2z
b = 3
a^2 = (2z)^2 = 2z^2
ab = (2z)*3 =6z
b^2 = 3^2 =9
a3 + b3 = (a + b)(a2 – ab + b2)
8z^2 +27 = (2z+3) (4z^2 -6z +9)
Ответ:
Step-by-step explanation:
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