Will mark brainliest In ΔABC, ∠A measures 132° and the values of b and a are 36 and 70, respectively. Find the remaining measurements of the triangle, and round your answers to the nearest tenth. **
∠B = 82.2°, ∠C = 62.8°, c = 40.6
∠B = 82.2°, ∠C = 62.8°, c = 30
∠B = 22.5°, ∠C = 25.5°, c = 40.6
∠B = 22.5°, ∠C = 25.5°, c = 30

∠B = 22.5°, ∠C = 25.5°, c = 40.6

Step-by-step explanation:

an angle and 2 sides are given. It just so happens that the angle is across from one of the sides. Using the Law of Sines to find the missing angle B first.

36 sin(132) = 70 sinB and

and

sinB=0.3821887674

B=(0.3821887674)

B = 22.5

Now, find C using the Triangle Angle-Sum Theorem .

C = 180 - 132 - 22.5

C = 25.5 degrees

Using the Law of Sines again with angle A and side A and angle C:

and

c=40.6

It is the third option there. Locate the third B and that's where you solution starts.

Step-by-step explanation: