Mathematics: Will, micah and sue went to dinner. will paid 1/3 of the dinner bill. micah and sue paid in the ratio of 2: 5. if sue paid $6 more than will, how much did the dinner cost

2nd oneStep-by-step explanation:...

Will, micah and sue went to dinner. will paid

mimithurmond03

06.01.2022

Answer : The dinner cost was, $ 42

Step-by-step explanation :

Let the dinner cost be, 'x'

Dinner cost paid by Will = $\frac{1}{3}\times x$

Remaining dinner cost = $(1-\frac{1}{3})x=\frac{2}{3}x$

The ratio of dinner cost paid by Micah and sue is 2:5

Dinner cost paid by Micah = $(\frac{2}{3}x)\times \frac{2}{7}=\frac{4}{21}x$

Dinner cost paid by Sue = $(\frac{2}{3}x)\times \frac{5}{7}=\frac{10}{21}x$

As, Sue paid dinner cost $6 more than Will.

That means,

$(\frac{10}{21}x)=\$ 6+(\frac{1}{3}\times x)$

$(\frac{10}{21}x)-(\frac{1}{3}\times x)=\$ 6$

$(\frac{1}{7}\times x)=\$ 6$

$x=\$ 6\times 7$

$x=\$ 42$

Thus, the dinner cost was, $ 42

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