Will pick ! the graph represents the function f(x) = 10(2)x.(image below)how would the graph change if the b value in the equation is decreased but remains greater than 1? check all that apply.a) the graph will begin at a lower point on the y-axis.b) the graph will increase at a faster rate.c) the graph will increase at a slower rate.d) the y-values will continue to increase as x-increases.e) the y-values will each be less than their corresponding x-values.

we are given

now, we can compare it with

we can find b

we get

now, we are given

How would the graph change if the b value in the equation is decreased but remains greater than 1

Let's take

b=1.8

b=1.6

b=1.4

b=1.2

now, we can draw graph

now, we will verify each options

option-A:

we know that all y-value will begin at y=0

because horizontal asymptote is y=0

so, this is FALSE

option-B:

we can see that

curve is moving upward when b decreases for negative value of x

but it is increasing slowly for negative values of x

so, this is FALSE

option-C:

we can see that

curve is moving upward when b decreases for negative value of x

but it is increasing slowly for negative values of x

so, this is TRUE

option-D:

we know that curves are increasing

so, the value of y will keep increasing as x increases

so, this is TRUE

option-E:

we can see that

curve is moving upward when b decreases for negative value of x

but it is increasing slowly for negative values of x

so, this is FALSE

$89.70 or $192.30

Step-by-step explanation:

All you have to do is multiply 26 by 3.45 and you get your answer. Which if you use a calculator it would say 89.7, to find the answer you just add a zero to the end.

If you're doing the second answer you multiply 30 by 3.45, then you take 26 and multiply by 3.45, after that you add them together and you get your answer.