Mathematics: With 2 questions you! show all work

With 2 questions you! show all work - id21061274, aspenwheeler6804

Ответ:

2003loganreed

08.06.2020

1:
1 - given
2 - defination of bisector
3 - reflexive
4 - given
5 - definition of bisector
6 - ASA congruence theorem

2: SQ = SQ would be the one I would use

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Ответ:

lalaween098

13.03.2022

Mathematics

$\frac{(2x - 3)}{(x + 4)(x - 2)} = \frac{1}{5} \\ \frac{2x - 3}{x {}^{2} - 2x + 4x - 8} = \frac{1}{5} \\ x {}^{2} - 2x + 4x - 8 = 5(2x - 3) \\ x {}^{2} + 2x - 8 = 10x - 15 \\ x {}^{2} + 2x - 10x = - 15 + 8 \\ x { }^{2} - 8x = - 7 \\ x {}^{2} - 8x + 7 = 0 \\ x {}^{2} - x - 7x + 7 = 0 \\ x(x - 1) + 7(x - 1) \\ x + 7 = 0 \\ x = - 7or \\ x - 1 = 0 \\ x = 1$

Step-by-step explanation:

x=7 or x=1

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