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EVOLVEDTANK40
15.07.2020 •
Mathematics
With 98% confidence interval and n = 25. Find left critical value for Zinterval.
0 -2.492
0 -2.05
0 -2.797
-2.326
Solved
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Ответ:
And
, the degrees of freedom are given by:
Then the critical value using the t distribution with 24 degrees of freedom is:
And the best solution would be:
0 -2.492
Step-by-step explanation:
For this problem we know that the sample size is n = 25. The confidence level is 98% or 0.98 then the significance would be:
And
, the degrees of freedom are given by:
Then the critical value using the t distribution with 24 degrees of freedom is:
And the best solution would be:
0 -2.492
Ответ:
The number is 218.
2=2×1
8=2×4