Worth 20 if you answer wrong or something not related to the question i will report you! : ) if f: 2x+1 and g: x^2 find a) f(3) b) g(7) c) fg(3) d gf(3) e) fg(7) f) fg(x)

A

f(x) = 2x + 1

f(3) = 2*3 + 1 = 7

B

g(x) = x^2

g(7) = 7^2

g(7)= 49

C

f(g(x)) = 2(g(x) + 1

f(g(x)) = 2 x^2 + 1

f(g(3) = 2* 3^2 + 1

f(g(3) = 19

D

g(f(x)) = (f(x))^2

g(f(x)) = (2x + 1)^2

g(f(3)) = (2*3 + 1)^2 = (6 + 1)^2 = 49

E

f(g(x)) = 2*g(x) + 1

f(g(x)) = 2*x^2 + 1

f(g(3)) = 2*3^2 + 1

f(g(3)) = 2 * 9 + 1

f(g(3)) = 18 + 1

f(g(3) = 19

F

f(g(x)) = 2(g(x)) + 1

f(g(x)) = 2*x^2 + 1  

162 square meters

Step-by-step explanation:

Given: l=2b, which means b=l/2 (1)

           h=1/3l (2)

To find: Area of the floor (lxb)

Solution: Volume of air in the room=972 cubic meters

We know that volume of a cuboid = l x b x h

                                                    ⇒   972 = l x l/2 x l/3 (from (1) and (2))

                                                    ⇒   972 = l³/6

                                                    ⇒   l³ = 972 x 6

                                                    ⇒   l³ = 5832

                                                    ⇒   l = 18    

Substituting l = 18 in (1), we get b = 9

∴ l x b = 18 x 9

          = 162 square meters

Hence the area of the floor is 162 square meters.

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