Write a function rule for the area of a rectangle with a length 2 ft less than three times it’s width. What is the area of the rectangle when it’s width is 2 ft?

9514 1404 393

  A(w) = w(3w-2)

  A(2) = 8 . . . . square feet

Step-by-step explanation:

For width w, the length will be 3w-2, two feet less than 3 times the width. The area is the product of length and width, so is ...

  A = WL

  A(w) = w(3w-2)

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To find the area for a width of 2, we put 2 where w is, then evaluate.

  A(2) = 2(3·2 -2) = 8 . . . . square feet

18/157

Step-by-step explanation

The key to solving this problem is to find the greatest common divisor of 72 and 628.

To find the greatest common divisor of 72 and 628, we list all of the factors of both numbers so we can compare the lists.

When we compared the factors of 72 (1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72) and 628 (1, 2, 4, 157, 314, 628) we found that 4 is the largest factor that they have in common.

Since 4 is the largest common factor of 72 and 628, 4 is also the greatest common divisor of 72 and 628.

Now, we divide both the numerator and denominator in 72/628 by the greatest common divisor as follows:

Numerator: 72/4 = 18

Denominator: 628/4 = 157

Then, we put the numerator and denominator that we are left with back together to get our answer. 72/628 to the simplest form is: 18/157