Write a linear equation in point-slope form that passes through the point (5,-2) and has a slope of -3. (Do not use any spaces) *

y + 2 = -3(x -5)

Step-by-step explanation:

The desired equation in general form is y - k = m(x - h).

Here, substitute 5 for x, -2 for y and -3 for m, obtaining:

y + 2 = -3(x -5)

Step-by-step explanation:

Begin by dividing by 5

2x + 4 = 3            

Is this written as 2^(x + 4) = 3? I think it is.

Take the log of both sides

log 2^(x + 4) = log(3)

(x + 4) * log(2) = log 3

log 2 = 0.30103

log 3 = 0.47712

(x + 4) = log2 / log3

x + 4 = 0.63093               Add 4 to both sides

x = -3.369                        Rounded to the nearest thousandth

If you mean the question exactly as it is written (the 4 is not part of the power)

5(2^x + 4) = 15

2^x + 4 = 3

2^x = 3 - 4

2^x = - 1

This can't be done 2 to any power should be >0.

if x>0 then this will give an ever increasing number

if xK0 then this will give an ever decreasing answer but still greater than 0.

No value will make 2^x go to something minus.

If I have misread this in some way, leave a note and I will get back to you.