Write a quadratic polynomial with roots 7 and -5

x²-2x-35

Step-by-step explanation:

(x-7)(x+5)

x²+5x-7x-35

x²-2x-35

A) 48m + 12 and 3(2m + 4 + 14m)

B) 48m + 12 is equivalent to 6(m + 2 + 7m) because if you distribute the 6 to everything inside the parentheses, you get 6m + 12 + 42m. This can be simplified further by adding 6m and 42m together, leaving you with 48m + 12.

C) m = 2

6(m + 2 + 7m)

6[2 + 2 + 7(2)]

6(4 + 14)

6(18)

108

3(2m + 4 + 14m)

3[2(2) + 4 + 14(2)]

3(4 + 4 + 28)

3(8 + 28)

3(36)

108

108 = 108

Step-by-step explanation:

A) You can simplify 6(m + 2 + 7m) by distributing the 6, (after simplification) resulting in 48m + 12.

Since 6/3 = 2, you can replace the 6 with 3 and multiply everything within the parentheses by 2.

B) This part was explained in the answer. If you have further questions please ask :)

C) I substituted m for 2 in both 6(m + 2 + 7m) and 3(2m + 4 + 14m). Since they both equal 108, the equations are equivalent.

Step-by-step explanation: